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Explanation:
Hope you know the wheastonbridge theorem i.e.
shown in the attachment.
Here 4/6 = 2/3 Thus the vertical resistance line having 4 ohm will be cancle out.
Now there are two paths for current
- 4 ohm + 2 ohm = 6 ohm
- 6 ohm + 3 ohm = 9 ohm
They both are in parallel hence its equivalent resistence will be 6×9 / 6+9 = 18/5 ohms.
Now by Ohms law V = IR
current i = V/R
= V × 5/18
= 5V/18 Volts
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