Question

ans this train question​

Answer 1

Answer:

625 m

Explanation:

90 km/h=25 m/s

Stopping distance s=u^2/2a

therefore s = 25^2/2×0.5

= 625/1

= 625 m

Answer 2

Explanation:

• initial velocity (u) = 90 km/h = 25 m/s
• final velocity (v) = 0 m/s
• acceleration (a) = -0.5 m/s²
• distance (s) = ?

We know that,

$\underline{\boxed{\sf v^2=u^2+2as}}$

$\sf \longmapsto 0 = (25)^2+2(-0.5)(s)$

$\sf \longmapsto 0=625-s$

$\sf \longmapsto -s=-625$

$\sf \longmapsto s = 625 \: m$