Physics, asked by patilp, 1 year ago

ans this wid explanation

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Answered by choudhary21
3
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______Correct⤵️ Answer⤵️______
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A. 0.7 kg/s

Force on rocket = udm/dt
∴ Rate ofd Combustion of fuel [dm/dt] = F/u = 210/300 = 0.7 kg/s
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Answered by Anonymous
4
Hii,

Here is your Answer by Sujeet yaduvanshi_______________________

Question:- if if the force on a rocket moving with velocity of 300m/s is 210N. then the rate of fuel combustion is??








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Answer:-)
Given that:- if if the force on a rocket moving with velocity of 300m/s is 210N.

then,

F= (dp/dt)

 or = (dmv/dt)

  or = v(dm/dt)
or,

210  = 300(dm/dt)
or

dm/dt = 0.7kg/s


that:s all
@Sujeet
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