ans this with steps....................
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Explanation:
pls find the attachment
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i) 2 A
ii) 3Ω
iii) 2A
iv) 16 V.
Explanation:
i) I = V/R
I = 10/5
I = 2A.
ii) Current is constant in a series connection
So, R = V / I.
From i), I = 2A.
Therefore, R = 6 / 2
R = 3Ω.
iii) Current is constant in a series connection
So, I = 2A.
iv) Voltage varies in series connection,
5Ω resistor consumes 10 V and 3Ω resistor consumes 6 V.
So, net Voltage = 10+6 = 16V.
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