Math, asked by laxmita, 11 months ago

ans thisssssssssss....

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Answered by kunal0912

In the given figure, OCBA is a cyclic Quadrilateral.

Hence, ∠AOC + ∠ ABC = 180°

so, ∠ABC = 180°-100° = 80°

And, ∠ABC + ∠CBD = 180° [Linear Pair]

so, ∠CBD = 180°-80° = 100°

Thus, ∠CBD = 100°

laxmita: its not a cyclic quad..

kunal0912: of course it is

kunal0912: all four vertices lie on circle

natasharaisinghani: i can answer ur question

kunal0912: sry

kunal0912: 1 min

natasharaisinghani: no kunal 0 is centre it doesn't lie on the circle

laxmita: no they don't lie

kunal0912: yup

Answered by prembhai0786

the correct answer is 50 guys.

remember the property of angle in the same segment.

laxmita: how we used this property pls explain

prembhai0786: u know na property

PriyaG3107: Angle coa = 100

PriyaG3107: Reflex angle coa = 240 , so angle cba = 120 (angle in the centre is double angle on anywhere on circle), angle cba+angle cbd = 180 (linear pair) , angle cbd = 60 degree

prembhai0786: reflex angle is 360-100=260

prembhai0786: how 240

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