Ans.
. Two dice are thrown simultaneously. Find the probability that the sum is
neither 7 nor 11.
Here, n (S) = 6*6 = 36 Let the events of
Answers
Answered by
1
Answer:
the probability is 7/9
Answered by
0
Answer:
The probability of getting a sum as 7 or 11 is
(1,6) (2,5) (3,4) (4,3) (5,2) (5,6) (6,1) (6,5)
8/36 is 2/9
The probability of not getting 7 or 11 is
1–2/9 is 7/9
Step-by-step explanation:
I hope explain
Similar questions