Math, asked by ertugrul79, 9 days ago

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Answered by kheteshwarkp
0

Step-by-step explanation:

Given tanp=5/4

So pq=4,QR=5

Use Pythagoras thm

PR=square root(16+25)=root 41

(ii) secR= PR/PQ=root 41/4

.(iii) 5sinR-3cosP=5*4/root41 - 3*4/root41

=20-12/root41

=8/root41

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Answered by iamasquidkid
0

Answer:

Paytm: 9867077620

Step-by-step explanation:

if 5tanp=4 therefore tan P= 4/5

tan= sin/cos

therefore tanP= sin53°,cos37°.

ii) Sec = 1/cos = 5/4

iii) 5 sin R- 3cos P= 3/4

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