Question

Ans with solution plzzz ​

Answer 1

Step-by-step explanation:

The Answer to this requires simple knowledge of Pythagoras theorem and Mensuration.

Area of an Equilateral triangle = √3 / 2 × (side)²

∴ Area of ΔAPB =  √3 / 2 × (AB)²

∴ Area of ΔBCQ =  √3 / 2 × (BC)²

∴ Area of ΔACR  =  √3 / 2 × (AC)²

∴ According to the question :-

( Area of ΔAPB + Area of ΔBCQ ) / ( Area of ΔACR )

= ( √3 / 2 × (AB)²  +  √3 / 2 × (BC)² )  /  (  √3 / 2 × (AC)² )

= ( √3 / 2 ( (AB)² + (BC)² )  )  /  ( √3 / 2 × (AC)² )

[ By Pythagoras Theorem we know that (AB)² + (BC)² = (AC)² ]

= ( √3 / 2 × (AC)² ) /  ( √3 / 2 × (AC)² )

= 1  

= 1 : 1

∴ The Answer to this question is option C) 1 : 1

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