Question

Ans with solution plzzz ​

Answer 1

Answer:

The value of A = 5

Step-by-step explanation:

Given,

$\sf {A = log_2\:log_2\:log_4\:256\:+\:2log_\sqrt{2}\:2}$

First we will solve: $\sf {log_2\:log_2\:log_4\:256}$

$\sf {log_2\:log_2\:log_4\:256}$ = $\sf {log_2\:log_2\:4}$

$\sf {log_2\:log_2\:log_4\:256}$ = $\sf {log_2\:2}$

$\sf {log_2\:log_2\:log_4\:256}$ = 1

Now, we will solve : $\sf {2\:log_\sqrt{2}\:2}$

$\sf {2\:log_\sqrt{2}\:2}$ = $\sf {log_\sqrt{2}\:2^{2}}$

$\sf {2\:log_\sqrt{2}\:2}$ = $\sf {log_\sqrt{2}\:4}$

$\sf {2\:log_\sqrt{2}\:2}$ = $\sf {log_\sqrt{2}\:4}$

$\sf {2\:log_\sqrt{2}\:2}$ = 4

$\sf {A = log_2\:log_2\:log_4\:256\:+\:2log_\sqrt{2}\:2}$

⇒ A = 1 + 4

⇒ A = 5

$<b><u>•°• The value of A = 5 </u></b>$