Question

ansewer this pleas ​

Answer 1

Answer:

Step-by-step explanation:

BY USING

                               [(a+b)³=a³+b³+3ab(a+b)]

a=sinθ

b=cosθ

sin³θ+cos³θ/sinθ+cosθ=(sinθ+cosθ)³-3sinθ*cosθ(sinθ+cosθ)/sinθ+cosθ

sinθ+cosθ[(sinθ+cosθ)²-3sinθ*cosθ]/sinθ+cosθ

sin²θ+2cosθsinθ+cos²θ-3sinθ*cosθ

1-sinθ*cosθ=R.H.S

PROVED

Answer 2

Answer:

idk

Step-by-step explanation:

idk