Question

ansewwww.............​

Answer 1

Answer:

maku nahi malum tu doushra sa puch

Answer 2

Answer:

let us consider that the object has traveled a distance 5 in time T under uniform acceleration . the distance traveled by the object is obtained by area enclosed within OABC under the velocity time graph AB

thus,

      the distance traveled by the object is given by

S = area OABC

• = area of the rectangle OADC + area of triangle ABD=OA×OC+   1/2 (AD×BD)

substituting  OA= U, OC=AD=T and BD = AT

we get , s=u×t+1/2ct×at

S= ut + 1/2 AT2

Explanation: