Question

Answe the Following pic is attached

Answer 1

Let us calculate the distance covered during acceleration.

We know that s=1/2at^2

Therefore, s=1/2*5*64

Which is equal to 160.

Now let us calculate the velocity after acceleration

v=u+ at

v=40

Distance covered in the rest 4 seconds is given by

s=vt

So s=160

Adding both the distances we get 320 m as the distance covered