Question

answer 1,2,3 question i will mark you as brainliest fast

Answer 1

Answer:

1. Ex 6.3 Class 8 Maths Question 1.

• What could be the possible ‘one’s’ digits of the square root of each of the following numbers?

(i) 9801

(ii) 99856

(iii) 998001

(iv) 657666025

Solution:

1. (i) One’s digit in the square root of 9801 maybe 1 or 9
2. (ii) One’s digit in the square root of 99856 maybe 4 or 6.
3. (iii) One’s digit in the square root of 998001 maybe 1 or 9.
4. (iv) One’s digit in the square root of 657666025 can be 5.

• Question 2.

Without doing any calculation, find the numbers which are surely not perfect squares.

1. (i) 15

(ii) 257

(iii) 408

• (iv) 441

Solution:

We know that the numbers ending with 2, 3, 7 or 8 are not perfect squares.

(i) 153 is not a perfect square number. (ending with 3)

(ii) 257 is not a perfect square number. (ending with 7)

(iii) 408 is not a perfect square number. (ending with 8)

(iv) 441 is a perfect square number.

Question 3.

Find the square roots of 100 and 169 by the method of repeated subtraction.

Solution:

Using the method of repeated subtraction of consecutive odd numbers, we have

(i) 100 – 1 = 99, 99 – 3 = 96, 96 – 5 = 91, 91 – 7 = 84, 84 – 9 = 75, 75 – 11 = 64, 64 – 13 = 51, 51 – 15 = 36, 36 – 17 = 19, 19 – 19 = 0

(Ten times repetition)

Thus √100 = 10

(ii) 169 – 1 = 168, 168 – 3 = 165, 165 – 5 = 160, 160 – 7 = 153, 153 – 9 = 144, 144 – 11 = 133, 133 – 13 = 120, 120 – 15 = 105, 105 – 17 = 88, 88 – 19 = 69, 69 – 21 = 48, 48 – 23 = 25, 25 – 25 = 0

(Thirteen times repetition)

Thus √169 = 13

Answer 2

Answer:

2,3,idk,2

Step-by-step explanation: