answer 12 question plz
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let there are n terms.
given,
first term (a) = 5
last term (l) = 45
sum (s) = 400
we know that s = n/2(a + l)
400 = n/2(5 + 45)
400 = 50n/2
50n = 400 × 2
n = 8 × 2
n = 16
16th term = 45
a + (n - 1)d = n term
5 + (16 - 1)d =45
5 + 15d = 45
15d = 45 - 5
15d = 40
d = 40/15
d = 2.66
given,
first term (a) = 5
last term (l) = 45
sum (s) = 400
we know that s = n/2(a + l)
400 = n/2(5 + 45)
400 = 50n/2
50n = 400 × 2
n = 8 × 2
n = 16
16th term = 45
a + (n - 1)d = n term
5 + (16 - 1)d =45
5 + 15d = 45
15d = 45 - 5
15d = 40
d = 40/15
d = 2.66
ram071987:
thanks
Answered by
0
Answer:
HEY MATE!!!!
HERE IS YOUR ANSWER,
S=400
L =45
a =5
S =n/2(a+L)
400 = n/2 (5+45)
400*2= n*50
800=50*n
800/50 = n
n = 16
L= 45
a16 = 45
a+15d= 45
5+15d = 45
15d = 45-5
15d = 40
d= 40/15
d=8/3
Hope it helps you.....
If it does please mark it as brainliest.....
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