answer 12th and 13th.. plzz.. _/\_
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12.a)OB
b) CD
c)area under vt graph=1/2×4×4= 8
13.If there are no forces applied to a system, the total momentum of the system remains constan
m1u1+m2u2=m1v1+m2v2
2×10+5×0=2×1+5×v2
20=2+5v2
v2=18/5
b) CD
c)area under vt graph=1/2×4×4= 8
13.If there are no forces applied to a system, the total momentum of the system remains constan
m1u1+m2u2=m1v1+m2v2
2×10+5×0=2×1+5×v2
20=2+5v2
v2=18/5
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Answered by
3
12. (i)In AB.
(ii)In CD.
(iii)Distance =slope=tan (x)=p/ b=4/4=1ms^-2
13. (i)It states that final momentum is equal to the initial momentum i.e., mv=MV.
OR
sum of total momentum is constant or zero provided system should be isolated.
(ii)m=2kg,v=1ms^-1,M=5kg,V=?
Now,
mv=MV
=> 2×1=5×V
So, V=0.4ms^-1.
thank u
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