Question

Answer 14 th answer plzz in this paper

Answer 1

(a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca (formula)

(a+b+c)^2 = a^2 + b^2+ c^2 + 2(ab+bc+ca)

12^2= 64+2(ab+bc+ca) ( Substituting the given values)

144= 64+2(ab+bc+ ca)

144–64 = 2(ab+bc+ca) (solving)

80= 2(ab+bc+ ca)

80/2 = ab+bc+ca

40 = ab+ bc+ ca

Ans: 40

Answer 2

${(a + b + c)}^{2} = 144$

${a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca) = 144$

$64 + 2(ab + bc + ca) = 144$

(ab+bc+ca)=40

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