Question

Answer 15th question..

Answer 1

HELLO DEAR,


LET THETA=(ALPHA)
$\frac{ \sin( \alpha ) }{ \sqrt{1 - { \sin}^{2} \alpha } } = \frac{ \sin( \alpha ) }{ \sqrt{ \cos ^{2} ( \alpha ) } } = \frac{ \sin( \alpha ) }{ \cos( \alpha ) } = \tan( \alpha )$
I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

I hope you understand