Question

answer 19 please it's urgent​

Answer 1

Let√3 be rational no.

√3=a/b where and b are integers ,b is not equal to 0 and a and b are co prime

(√3)^2=a^2/b^2

3=a^2/b^2

3b^2=a^2

A divides 3

a=3c for any integer c

3b^2=(3c)^2

3b^2=9c^2

b^2=3c^2

b divides 3 also

But we assumed that a and b are co prime

So this is a contradiction to our assumption that √3is rational.

√3 is irrational.