Question

Answer 1st with the CORRECT answer to be marked as brainlist.

Answer 1

Given :-

• The Whole Shape is :- One Rectangle + One Right Angle ∆.
• Sides of Rectangle = 5m & 8 m.
• Base of Complete Quadrilateral = 12m.

Formula used :-

• Area of Rectangle = Length * Breadth.
• Area of Right angle ∆ = (1/2) * Base * Height .

Solution :-

→ Area of Figure with Rectangle = L * B = 5 * 8 = 40m² -------- Equation (1).

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Now,

→ Base of Right Angle ∆ = 12 - 5 = 7m.

→ Height of Right angle ∆ = 8 - 3 = 5m.

So,

→ Area of Right Angle ∆ = (1/2) * Base * Height = (1/2) * 7 * 5 = (35/2) = 17.5m². ------------ Equation (2).

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Hence,

→ Area of Complete Figure = Rectangle Area + Area of Right angle ∆.

→ Required Area = Equation (1) + Equation (2).

→ Required Area = 40 + 17.5

→ Required Area = 57.5 m². (Ans.) (Option A).

Hence, Area of Given Figure is 57.5m².

Answer 2

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$\huge\tt{GIVEN:}$

• A figure which could be divided into a rectangle and a right angled triangle

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$\huge\tt{TO~FIND:}$

• The area of the given figure

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$\huge\tt{SOLUTION:}$

➩Area of The Rectangle = (5×8)m² = 40m²

➠Base of right angled triangle = (12-5)=7m

➠Height of right angled triangle = (8-3)=5m

➩Area of the right angled triangle = ½ × Base × Height = (½ × 7 × 5) = 17.5m²

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➠Area of the whole figure = Area of Rectangle + ➠Area of the right angled triangle

➠Total area = (40+17.5)m²

➠Total area = 57.5m²

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