Answer=20 days. How to do this?
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Answered by
1
Number of days in April = 30
So he would receive = 100×30 = ₹3000
But he received ₹1900.
Let's say he was absent for x days.
So instead of getting ₹100, he would lose ₹10 as fine.
So total loss in an absent day = ₹100 + ₹10 = ₹110.
Total loss in x days = 110×x = ₹110x
according to the question,
3000 - 110x = 1900
=> -110x = 1900 - 3000 = -1100
=> 110x = 1100
=> x = 1100/110
=> x = 10 days.
So he was absent for 10 days in April.
______________________________
If you want to check:
absent = 10 days
present = 30 - 10 = 20 days
payment for 20 days = 20×100 = ₹2000
fine = 10×10 = ₹100
payment for the month = 2000-100=₹1900
so answer is correct
So he would receive = 100×30 = ₹3000
But he received ₹1900.
Let's say he was absent for x days.
So instead of getting ₹100, he would lose ₹10 as fine.
So total loss in an absent day = ₹100 + ₹10 = ₹110.
Total loss in x days = 110×x = ₹110x
according to the question,
3000 - 110x = 1900
=> -110x = 1900 - 3000 = -1100
=> 110x = 1100
=> x = 1100/110
=> x = 10 days.
So he was absent for 10 days in April.
______________________________
If you want to check:
absent = 10 days
present = 30 - 10 = 20 days
payment for 20 days = 20×100 = ₹2000
fine = 10×10 = ₹100
payment for the month = 2000-100=₹1900
so answer is correct
Answered by
0
Let the number of the days the man worked be 'x'. Since April has 30 days, The days he did not work would be '30-x'.
He gets 100Rs for 1 day work, therefore for x days he will get: 100×x = 100x Rs
He loses 10 Rs per day in which he doesn't do work, So the Rs that he will lose in (30-x) days will be: 10(30-x) Rs
Now the money he got = Payment - Fine
Therefore,
Therefore, he worked for 20 Days.
He gets 100Rs for 1 day work, therefore for x days he will get: 100×x = 100x Rs
He loses 10 Rs per day in which he doesn't do work, So the Rs that he will lose in (30-x) days will be: 10(30-x) Rs
Now the money he got = Payment - Fine
Therefore,
Therefore, he worked for 20 Days.
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