Question

answer 20thquestion

Answer 1

please mark this answer as brainlist

Answer 2

According t o given sum,

I will take theta as alpha for my convenience.

$\sin( \alpha ) \cos( \alpha ) + \frac{ \sin( \alpha ) \cos(90 - \alpha ) \cos( \alpha ) }{ \sec(90 - \alpha ) } + \frac{ \cos( \alpha ) \sin(90 - \alpha ) \sin( \alpha ) }{ \csc(90 - \alpha ) } - 2 \sin(90 - \alpha ) \cos(90 - \alpha )$

$\sin( \alpha ) \cos( \alpha ) + \frac{ \sin( \alpha ) \sin( \alpha ) \cos( \alpha ) }{ \csc( \alpha ) } + \frac{ \cos( \alpha ) \cos( \alpha ) \sin( \alpha ) }{ \sec( \alpha ) } - 2 \sin( \alpha ) \cos( \alpha )$

$( { \sin( \alpha ) })^{3} \cos( \alpha ) + ({ \cos( \alpha ) })^{3} \sin( \alpha ) - \sin( \alpha ) \cos( \alpha )$

$\sin( \alpha ) \cos( \alpha ) ( { \sin( \alpha ) }^{2} + { \cos( \alpha ) }^{2} - 1)$

$\sin( \alpha ) \cos( \alpha ) (1 - 1)$

$\sin( \alpha ) \cos( \alpha ) (0)$

$0$

Hence the answer is 0.

:-)hope it helps u.

pls mark as brainliest.