Answer 27,28 and 29 with reason.
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27) Velocity = dx/dt
Hence v = 8t and acceleration = dv/dt
and a=8
Hence v-t graph must be a st. line with positive slope and a-t graph must be a line which is parallel to y-axis
29) The displacement will be the area under the graph
Area = 1/2 ×2×8 + 2×8 + 1/2×2×8 - 1/2×2×5 - 1/2×2×5
= 8+16+8-5-5
= 22 metres
As distance is a scalar quantity the same area for displacement will be changed as = 8+16+8+5+5
= 42 metres
28) (a) It shows us that the body first slows down , comes to rest and then it starts moving in the opposite direction.
(b) The body first moves with a constant velocity and then it constantly slows down......
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