Question

answer 41st qn....!!!!!​

Answer 1

Answer: π= 5.27 × 10^-3 atm

Explanation:

Given,

Mass of K2SO4(w) = 25 mg = 0.025g (1 g = 1000 mg )

Volume(V) = 2 liter

T = 25 + 273 = 298 K (add 273 to convert in Kelvin)

The reaction of dissociation of K2SO4

K2So4 → 2K+ + SO42-

Number if ions produced = 2+ 1 = 3

So van’t Hoff factor i = 3

formula of Osmotic pressure:

$\pi = i \frac{n}{v} rt$

$\pi = i \frac{w}{m} \frac{1}{v} rt$

Gas constant, R = 0.0821 L atm K^-1mol^-1

Molar mass of K2SO4 ,M = 2 × 39 + 1 × 32 + 4 × 16 = 174 g mol^-1

Now putting the values we get ,

$\pi = 3 \times \frac{0.025}{174} \times \frac{1}{2} \times 0.0821 \times 298$

π= 5.27 × 10^-3 atm

Hope it helps....✌