Question

Answer 5 th question
Please answer correctly
and answer fastly​

Answer 1

Answer:

In triangle ABE,

AB=5/2cm.

BE=2 3/4cm=11/4cm.

EA=3 3/5cm=18/5cm.

Perimeter of triangle ABE=a+b+e.

=5/2+11/4+18/5.

=50+55+72/20. (Because LCM of 2,4 & 5 is 20).

=177/20cm. (or). 8 17/20cm. (or). 8.85cm.

In rectangle BCDE,

BC=ED=7/6cm. (Because BC parallel to ED.

BE=CD=2 3/4cm=11/4cm. (Because BE parallel to CD).

Perimeter of rectangle=2(length+breadth).

=2(7/6+11/4).

=2(14+33/12). (Because LCM of 6 & 4 is 12).

=2(47/12).

=47/6cm. (or). 7 5/6cm. (or). 7.8333......cm.

I think this is your answer.

Answer 2

$\large\fcolorbox{red}{cyan}{Triangle\:Has\:More\:Perimeter}$

Explaination :-

First , Lets calculate The Perimeter of Triangle

• Side A = $\frac{5}{2}$

• Side B = $3\frac{3}{5}$

• Side C = $2\frac{3}{4}$

$\color{purple}{Perimeter\:Of\:Triangle = Sum\:Of\:All\:Sides} \\ =>\bf{Lets\:Put\:The\:Values} \\ => \frac{5}{2}+3\frac{3}{5}+2\frac{3}{4} \\ =>\frac{5}{2}+\frac{18}{5}+\frac{11}{4} \\ => \frac{50+72+55}{20} \\ => \boxed{\frac{177}{20}\:or\:8.85}$

Now , Perimeter of Rectangle :-

• Length = $3\frac{2}{4}$

• Breadth = $\frac{7}{6}$

$\color{orange}{Perimeter\:Of\:Rectangle = 2(l+b)} \\ => 2(\frac{11}{4}+\frac{7}{6}) \\ => 2(\frac{33+14}{12}) \\ => 2 \times \frac{47}{12} \\ => \boxed{\frac{94}{12}\:or\:7.838}$

Hope it helped