answer 5 th the correct answer would get the brainliest one
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Given :
ΔPQR is an equilateral traingle.
To prove :
ar (PQM) = ar (PRM)
Proof :
As ΔPQR is an equilateral traingle ,
PQ = QR = PR
In Δ PQM and ΔPRM ,
PQ = PR (Given)
PM = PM (Common)
∠PMR =∠PMQ (Each 90°)
∴ Δ PQM ≅ ΔPRM [ RHS Rule ]
∴ ar (PQM) = ar (PRM)
ΔPQR is an equilateral traingle.
To prove :
ar (PQM) = ar (PRM)
Proof :
As ΔPQR is an equilateral traingle ,
PQ = QR = PR
In Δ PQM and ΔPRM ,
PQ = PR (Given)
PM = PM (Common)
∠PMR =∠PMQ (Each 90°)
∴ Δ PQM ≅ ΔPRM [ RHS Rule ]
∴ ar (PQM) = ar (PRM)
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meetuk:
thnx u
this mean that we can do by cpct
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