Question

Answer 60 th question pleaseeeeeeeeee

Answer 1

Hope u like my process
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For first body,

Mass = m1
Let force be x
Acceleration = 6m/s²

Since force = mass × Acceleration
So, x = 6 × m1

For second body,

Mass = m2
Force = same = x = 6 × m1
Acceleration = 3m/s²

So, x = 3× m2
or, 6m1 = 3m2
or, m1 / m2 = ½

If both are joined,

Total mass = m1 + m2
Force = same = 3 × m2
Acceleration =?

If force = mass × Acceleration,
Then, Acceleration = force /mass

So required Acceleration =
$\frac{3m2}{m1 + m2} \\ = \frac{3}{ \frac{m1 + m2}{m2 } } \\ = \frac{3}{ \frac{m1}{m2} + 1} = \frac{3}{ \frac{1}{2} + 1} \\ = \frac{3 \times 2}{3} = 2$




Thus required acceleration is 2 m/s²

Hope this is ur required answer
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