Question

ANSWER 9 ONE ..................

Answer 1

Answer:

the question is not clear

Answer 2

Answer:

Let s1 be the distance travelled during its acceleration ...a=2 t1=10

we know that s1=ut+1/2at²

since u=0

s1=1/2(2)(10)(10)

s1=100m and also v=u+at

v=20m/s

now let s2 be the distance travelled during its declaration ...a=-1,u=20,t=10

now s2 = 200-50=150

total distance travelled =100+150=250m