Question

Answer 9 th question
Anewer with proper steps....​

Answer 1

$4 {x}^{3} + 8 {x}^{2} - x - 2 = 0 \\ \\ 4 {x}^{2} (x + 2) - 1(x + 2) = 0 \\ \\ (4 {x}^{2} - 1)(x + 2) = 0 \\ \\ (x + 2)(4 {x}^{2} + 2x - 2x - 1) = 0 \\ \\ (x + 2)(2x(2x + 1) - 1(2x + 1)) \\ \\ (x + 2)(2x + 1)(2x - 1) = 0 \\ \\ x = - 2 \\ \\ x = - \frac{1}{2} \\ \\ x = \frac{1}{2}$

Now

$2x + 3 \\ \\ 1.. \\ \\ 2( - 2) + 3 \\ \\ = - 1 \\ \\ 2.. \\ \\ 2( - \frac{1}{2} ) + 3 \\ \\ = 2 \\ \\ 3.. \\ \\ 2( \frac{1}{2} ) + 3 \\ \\ = 4$

Option A

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Answer 2

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