Question

answer 9and 10th both
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Answer this and previous questions. plz
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Answer 1

ANS 9

Here, r = 4. 2/ 2 m = 2.1 m, h = 4.5 m

(i) Curved surface area of the storage tank = 2πrh

= 2 × 22 7 × 2.1 × 4.5 m2 = 59.4 m2

Ans. (ii) Total surface area of the tank = 2πr (h + r)

= 2 × 22/ 7 × 2.1 (4.5 + 2.1) m2 = 44 × 0.3 × 6.6 m2 = 87.12 m2

Let the actual area of steel used be x m2.

Area of steel wasted = 1/ 12 of x m2 = x/ 12 m2. ...

(i) ∴ area of the steel used in the tank =( x − x /120 )m2 = 11/ 12 x m2 ⇒ 87.12 = 11/ 12 x ⇒ x = 87. 12x 12/ 11 = 95.04 m2

Hence, 95.04 m2 of steel was actually used

Answer 2

Step-by-step explanation:

this will help you.....9 no. bhi hai dekh lo..