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A copper rod of diameter 1 cm and length 8 cm is drawn into a wire of length 18 cm of uniform thickness find the thickness of the wire
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question ....
❤✌ ANSWER✌❤
A copper rod of diameter 1 cm and length 8 cm is drawn into a wire of length 18 cm of uniform thickness find the thickness of the wire.
answer.....
Given diameter of the copper rod = 1 cm
So, radius(r) of the copper rod = 1/2 cm
Let R is the radius of the cross section(circular) of the wire.
Now, according to the question,
πR2 *(18*100) = π(1/2)2 *8
=> R2 *(18*100) = (1/2)2 *8
=> R2 *(18*100) = 8/4
=> R2 *(18*100) = 2
=> R2 = 2/(18*100)
=> R2 = 1/(9*100)
=> R = √{1/(9*100)}
=> R = 1/(3*10)
=> R = 1/30
Now, thickness of the wire = 2r = 2 * 1/30 = 2/30 = 1/15 = 0.067 cm
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answer
question ....
❤✌ ANSWER✌❤
A copper rod of diameter 1 cm and length 8 cm is drawn into a wire of length 18 cm of uniform thickness find the thickness of the wire.
answer.....
Given diameter of the copper rod = 1 cm
So, radius(r) of the copper rod = 1/2 cm
Let R is the radius of the cross section(circular) of the wire.
Now, according to the question,
πR2 *(18*100) = π(1/2)2 *8
=> R2 *(18*100) = (1/2)2 *8
=> R2 *(18*100) = 8/4
=> R2 *(18*100) = 2
=> R2 = 2/(18*100)
=> R2 = 1/(9*100)
=> R = √{1/(9*100)}
=> R = 1/(3*10)
=> R = 1/30
Now, thickness of the wire = 2r = 2 * 1/30 = 2/30 = 1/15 = 0.067 cm
hope it is helpful ✌️✌️✌️✌️✌️
please mark as brilliant ✌️✌️✌️
Answered by
3
Answer:
Step-by-step explanation:
Both copper rod and wire are in the shape of cylinder
diameter of rod = 1 cm
Radius r1 of rod = 1/2 cm
height h1 of rod = 8 cm
height h2 of wire = 18 cm
Let the Radius of wire be r2
Equating the volumes of two
πr1^2h1 = πr2^2h2
π gets cancelled
(1/2)^2 × 8 = r2^2 × 18
2 = 18 r2^2
r2^2 = 2/18
r2 = (√2/√18)
r2 = √2/3√2) = 1/3 cm
Hence thickness of wire = 1/3 cm
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