Answer....
A man walks along a park of dimensions 400m. Calculate the magnitude of displacement.
HappiestWriter012:
the dimensions 400*400
it is a square park
Answers
Answered by
1
Hi friend,
ABCD is the park.
Displacement will be from A to C.
(400)^2+(400)^2=(AC)^2
(160000 + 160000=AC^2
320,000= AC^2
400 root 2=AC
Its wrong I think..
Hope it helps...
ABCD is the park.
Displacement will be from A to C.
(400)^2+(400)^2=(AC)^2
(160000 + 160000=AC^2
320,000= AC^2
400 root 2=AC
Its wrong I think..
Hope it helps...
:)
how do u know park is in rectangular shape
Answered by
1
Hi friend,
Magnitude (distance)=400+400
=800m^2
Displacement=√400^2+400^2
√160000×2
=400√2 m
Hope this helps you...
Magnitude (distance)=400+400
=800m^2
Displacement=√400^2+400^2
√160000×2
=400√2 m
Hope this helps you...
If any thing wrong sorry for my answer
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