Answer aati hogi to krna.
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11.
According to the question,
For the first km the fare is Rs 10 and for the subsequent kms it is Rs 4.50 per km.
Therefore the linear equation is
10 + 4.50(X 1) = Y
-> 10 + 4.5X 4.5 = Y
-> 4.5X + 5.5 = Y
-> 4.5X - Y = -5.5
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12.
in the parallelogram sum of adjacent angle is 180°
angle A + angle D = 180 °
in ΔAOD
angle OAD + angle ODA + Angle AOD = 180°
Angle A /2 + Angle D / 2 + angle AOD = 180°
90° + angle AOD = 180°
Angle AOD = 90°
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13.
PQ ∥ AC & SR ∥ AC therefore PQ ∥ SR and PQ=SR. Hence, a quadrilateral with opposite sides equal and paralle is a parallelogram. Therefore PQRS is a parallelogram.
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14.
In the figure attached, there is a circle having AB as the diameter and angle ADC = 30 °
Since angle subtended by the diameter on the circumference of a circle is 90°,
M angle ACB = 90°
Sum of opposite angles of a quadrilateral in a circle is 180°.
Therefore, angle ADC + angle CBA = 180°
130° + angle CBA = 180°
angle CBA = 180 - 130 = 50°
Now in ΔBAC,
angel BAC + angle ACB + angle CBA = 180°
angle BAC + 90°+ 50° = 180°
angle BAC = 180° - 140° = 40°
Therefore, measure of angle BAC is 40°.
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9th
Maths
Quadrilaterals
Theorems Related to Parallelograms
ABCD is a parallelogram. Th...
MATHS
ABCD is a parallelogram. The angle bisectors of ∠ A and ∠D meet at O. The measure of ∠AOD is:
December 27, 2019avatar
Khan Pandey
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ANSWER
Let ∠A be 2x
Let ∠D be 2y
Since AB∥DC , sum of angles on same side of the transversal AD will be 180
o
=>2x+2y=180
o
x+y=90
o
After bisection of angles A and D, we get ∠1=x and ∠2=y as per the given figure.
Now in △AOD, we have
x+y+∠AOD=180
o
90
o
+∠AOD=180
o
=>∠AOD=90
o