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In ∆DAY & ∆CBX
since , Ax = BY (given) ,so , AX + XY = BY + XY , so AY = BX
DA = CB (GIVEN)
& ∠DAY = ∠CBX (90°)
By , SAS , they are congruent
since , Ax = BY (given) ,so , AX + XY = BY + XY , so AY = BX
DA = CB (GIVEN)
& ∠DAY = ∠CBX (90°)
By , SAS , they are congruent
Anonymous:
Sorry it is , Ay = BX ( AX+XY = XY+BY)
Answered by
1
given,
DA = CB
AX = BY
to prove :- ΔDAY ≈ ΔCBX
proof:-
DA = CB
∠A = ∠B = 90°
AX = BY
therefore,
AX + XY = BY + XY
AY = BX (∵ if equals are added to equals the wholes are equal)
therefore ΔDAY ≈ ΔCBX
by SAS congruence rule.
i hope that this will help u.......................^_^
DA = CB
AX = BY
to prove :- ΔDAY ≈ ΔCBX
proof:-
DA = CB
∠A = ∠B = 90°
AX = BY
therefore,
AX + XY = BY + XY
AY = BX (∵ if equals are added to equals the wholes are equal)
therefore ΔDAY ≈ ΔCBX
by SAS congruence rule.
i hope that this will help u.......................^_^
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