Question

Answer above question​

Answer 1

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Given figure, if AB || CD || EF, PQ || RS, RQD=25o and CQP=60o,

Then ∠SRB=∠CQP=60

OR ∠QRA=∠RQD=25

So ∠ARS+∠SRB=180

∴∠ARS=120−60=120

∠QRS=∠ARS+∠QRA=120+25=145

✏️ I hope it will help you