ANSWER above question plz with explinetion on book
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rathodparshram:
Give correct answer
I think that the given is not sufficient to prove
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Step-by-step explanation:
here in traingle ABD and ∆ ADC
AD = AD { common side}
<ADB= < ADC { 90° }
and BD = DC ( median devide the base equally)
therefore by S.A.S { side angle side} congurency ....
∆ ABD = ∆ ACD
In question that means it is not given that
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