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sin theta = 12 /13 .........1
and sin theta is also equal to p / h .........2
hence equation 1 and 2 are equal
12/13 = p/h
p = 12 and h = 13
by Pythagoras theorem, we will find base (b)
h^2 = p^2 + b^2
then b = 5
hence tan theta = p/b
=12/5
and cos theta = b / h
= 5 / 13
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