Question

answer accirding to questio'​

Answer 1

refer to the attachment .....

Answer 2

SOLUTION

We have,

AL perpendicular to BC

CM perpendicular to AB

=)In ∆OMA & ∆OLC

angleMOC = angleLOC

{Vertically opposite angles}

=)angleAMO= angleCLO {each 90°}

=) Then, ∆OMA congruent ∆OLC

{by AA similarity}

Therefore,

OA/OC= OM/OL

{Corresponding parts of similar ∆ are proportional}

hope it helps ✔️