Question

Answer all correctly please. ​

Answer 1

Answer:

1)In case of concave spherical mirror focal length, f=R/2, where R is radius of curvature of the mirror. Here R=40 cm ,hence f=20 cm.

2)if an object is placed at 30 cm in front of the mirror so as to obtain the real image. The image formed is real, inverted and is of the same size as the object.

3)The lens formula is 1v−1u=1f, where,

The lens formula is 1v−1u=1f, where,u is the distance of the object from the lens ,

The lens formula is 1v−1u=1f, where,u is the distance of the object from the lens ,v is the distance of the image from the lens, and,

The lens formula is 1v−1u=1f, where,u is the distance of the object from the lens ,v is the distance of the image from the lens, and,f is the focal length.

The lens formula is 1v−1u=1f, where,u is the distance of the object from the lens ,v is the distance of the image from the lens, and,f is the focal length.It may be noted that for a convex lens u is always negative and f is always positive.

The lens formula is 1v−1u=1f, where,u is the distance of the object from the lens ,v is the distance of the image from the lens, and,f is the focal length.It may be noted that for a convex lens u is always negative and f is always positive.⇒1v=1f+1u=u+fuf.

The lens formula is 1v−1u=1f, where,u is the distance of the object from the lens ,v is the distance of the image from the lens, and,f is the focal length.It may be noted that for a convex lens u is always negative and f is always positive.⇒1v=1f+1u=u+fuf. ⇒v=ufu+f.

The lens formula is 1v−1u=1f, where,u is the distance of the object from the lens ,v is the distance of the image from the lens, and,f is the focal length.It may be noted that for a convex lens u is always negative and f is always positive.⇒1v=1f+1u=u+fuf. ⇒v=ufu+f. ⇒ Magnification =vu=fu+f.

The lens formula is 1v−1u=1f, where,u is the distance of the object from the lens ,v is the distance of the image from the lens, and,f is the focal length.It may be noted that for a convex lens u is always negative and f is always positive.⇒1v=1f+1u=u+fuf. ⇒v=ufu+f. ⇒ Magnification =vu=fu+f. Since u is always negative and f is always positive the denominator of RHS is negative as long as the distance of the object from the mirror is greater than the focal length.

The lens formula is 1v−1u=1f, where,u is the distance of the object from the lens ,v is the distance of the image from the lens, and,f is the focal length.It may be noted that for a convex lens u is always negative and f is always positive.⇒1v=1f+1u=u+fuf. ⇒v=ufu+f. ⇒ Magnification =vu=fu+f. Since u is always negative and f is always positive the denominator of RHS is negative as long as the distance of the object from the mirror is greater than the focal length.It can thus be seen that as the magnitude of the distance of the object from the mirror decreases (magnitude of u decreases), the magnification increases from 0 when u=−∞ to 1 when u=−2f to ∞ when u=−f. The image is real.

The lens formula is 1v−1u=1f, where,u is the distance of the object from the lens ,v is the distance of the image from the lens, and,f is the focal length.It may be noted that for a convex lens u is always negative and f is always positive.⇒1v=1f+1u=u+fuf. ⇒v=ufu+f. ⇒ Magnification =vu=fu+f. Since u is always negative and f is always positive the denominator of RHS is negative as long as the distance of the object from the mirror is greater than the focal length.It can thus be seen that as the magnitude of the distance of the object from the mirror decreases (magnitude of u decreases), the magnification increases from 0 when u=−∞ to 1 when u=−2f to ∞ when u=−f. The image is real.When −f <u<0, v is negative and the magnification is negative.

The lens formula is 1v−1u=1f, where,u is the distance of the object from the lens ,v is the distance of the image from the lens, and,f is the focal length.It may be noted that for a convex lens u is always negative and f is always positive.⇒1v=1f+1u=u+fuf. ⇒v=ufu+f. ⇒ Magnification =vu=fu+f. Since u is always negative and f is always positive the denominator of RHS is negative as long as the distance of the object from the mirror is greater than the focal length.It can thus be seen that as the magnitude of the distance of the object from the mirror decreases (magnitude of u decreases), the magnification increases from 0 when u=−∞ to 1 when u=−2f to ∞ when u=−f. The image is real.When −f <u<0, v is negative and the magnification is negative.As the magnitude of the distance of the object from the mirror decreases further, the magnitude of the magnification reduces from ∞ when u=−f to 1 when u=0. The image is virtual.

4)Convex mirror as it has a wide range of viewing angle through the object appear smaller than the reality. but You can see the full image of tree or building.

5) c) between pole and 20 cm

Explanation:

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