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you can easily get this type of question in ncert sites and more materials
look one advise no is going to solve maths for you brother
look one advise no is going to solve maths for you brother
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HEY FRIEND
HERE IS YOUR ANSWER
Here triangle ABC is a right angled triangle. [ since <B = 90°]
So according to Pythagoras' theorem,
(Perpendicular) ^2 + (Base)^2 = (Hypotenuse)^2
or, (AB)^2 + (BC) ^2 = (AC)^2
or, (AB)^2 = (17)^2 - (15)^2
or, (AB)^2 = 64
or, AB = +8 or -8
Length can never be negative.
So AB = 8 cm. (a) ----- Ans.
Area of a triangle = 1/2 * Base * Height
= (1/2 *8 * 15 )sq. cm.= 60 sq. cm. (b)------Ans.
Now considering AC as base
1/2 * AC * BD = 60 [as area remains constant]
or, BD = 60*2/17
or, BD = 7. 058 (c) ----- Ans.
HOPE IT HELPS YOU
MARK IT AS BRAINLIEST.
HERE IS YOUR ANSWER
Here triangle ABC is a right angled triangle. [ since <B = 90°]
So according to Pythagoras' theorem,
(Perpendicular) ^2 + (Base)^2 = (Hypotenuse)^2
or, (AB)^2 + (BC) ^2 = (AC)^2
or, (AB)^2 = (17)^2 - (15)^2
or, (AB)^2 = 64
or, AB = +8 or -8
Length can never be negative.
So AB = 8 cm. (a) ----- Ans.
Area of a triangle = 1/2 * Base * Height
= (1/2 *8 * 15 )sq. cm.= 60 sq. cm. (b)------Ans.
Now considering AC as base
1/2 * AC * BD = 60 [as area remains constant]
or, BD = 60*2/17
or, BD = 7. 058 (c) ----- Ans.
HOPE IT HELPS YOU
MARK IT AS BRAINLIEST.
haris77:
Thank you
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