answer all please 2nd roman
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Hey don't worry ,here is your answer..
Given,
area of a rectangle =(length) (breadth) =154-eq1
breadth =11cm- eq2.
substitute breadth value on eq-1
=(length)(11)=154.
=length =154/11
length =14cm.
Perimeter of a rectangle =2h(length+breadth).
=2(14+11).
=2(25).
=50cm^2.
Please mark this as a brainliest answer
Given,
area of a rectangle =(length) (breadth) =154-eq1
breadth =11cm- eq2.
substitute breadth value on eq-1
=(length)(11)=154.
=length =154/11
length =14cm.
Perimeter of a rectangle =2h(length+breadth).
=2(14+11).
=2(25).
=50cm^2.
Please mark this as a brainliest answer
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