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a. Area = 25.37 cm²
=> l × b = 2537/100
=> 59/10 × b = 2537/100
=> b = 2537/100 × 10/59
=> b = 4.3
.°. b = 4.3 cm
b. 2(y - 1) = y - 10
=> 2y - 2 = y - 10
=> 2y - y = - 10 + 2
=> y = -8
.°. y = -8
c. 6% of 550m
= 6/100 × 550 m
= 33 m
d. Let,
the number of chocolates A will get be 2x
the number of chocolates B will get be 3x
the number of chocolates C will get be 5x
Therefore,
2x + 3x + 5x = 500
=> 10x = 500
=> x = 500/10
=> x = 50
.°. x = 50
Therefore,
the number of chocolates A will get = 100
the number of chocolates B will get = 150
the number of chocolates C will get = 250
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