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Answers
Answer:
Q10:
A's capacity =1/10
B's capacity =1/15
When they work together = 1/10 + 1/15
=>3/30+2/30
=>5/30=>1/6
Therefore they will finish the work in 6 days
Q11:
When A and B works together=1/15
B and C= 1/12
C and A =1/20
By these there equation we have to solve for each member
ie
Adding all equation =>2A+2B+2C=1/15+1/12+1/20
2(A+B+C)=(4+5+3)/60
2(A+B+C)=12/60
dividing both side by 2
A+B+C=6/60
=>A+B+C=1/10
Therefore when they work together they can finish the work in 10 days
Q12:
Gita =(1/3)/6
Gita=>1/3*6=>1/18
Salma=>(1/2)/3
Salma=>1/2*3=1/6
When they work together =1/18+1/6
=>(1+3)/18
=>4/18
=>2/9
From above they can finish 2 works in 9 days
but question asked for 1 work therefore 9/2=4.5 days or 4½ days
Sorry I can't continue I need to go now Sorry
Answer:
Q 10 Number of days A required do a piece of work : 10 Number of days B required do a piece of work : 15 Work done by A in one day: 1/10
Work done by B in one day: 1/15
Work done by A and B together in one day: 1/10+1/15=5/30=1/6
Therefore they can work in six days
Q 11 A + B can do the work in 12 days.
In a single day A+B will do 1/12 th portion of the work.
B+C can do the work in 15 days.
In a single day B+C will do 1/15 th portion of the work.
A + C can do the work in 20 days.
In a single day A+C will do 1/20 th portion of the work.
In a day (A+B)+(A+C)+(C+A) will do=(1/12)+(1/15)+(1/20) portion of the work.
2(A+B+C)=(1/12)+(1/15)+(1/20)=1/5 portion of the work.
Then, (A+B+C) will do =1/10 portion of the work in a day
A+B+C will complete the work in 10 days.
C can finish the portion of the work in a single day = Single day work of (A+B+C)-(A+B)=(1/10)-(1/12)=1/60
So C alone can finish the work in just 60 days.
B can finish the portion of the work in a single day = Single day work of (A+B+C)-(A+C)=(1/10)-(1/20)=1/20
So B alone can finish the work in just 20 days.
A can finish the portion of the work in a single day = Single day work of (A+B+C)-(B+C)=(1/10)-(1/15)=1/30
So A alone can finish the work in just 30 days.
Q 12 gita -18 days
salma-6 days
Q 13 It is given that 2 men or 3 women can do a piece of work in 16 days .
2 men = 3 women
We have to find in how many days can 4 men and 6 women can do the same work.
4 men + 6 women = 6 women + 6 women = 12 women
3 women can do a piece of work in 16 days and 12 women can do the same work in D days.
3*16=12*d
48=12d
divide both sides by 12 we get
4=d
Therefore the 4 men and 6 women can do the same work in 4 days.