Chemistry, asked by bharati27, 10 months ago

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Answers

Answered by siril
1

82) 3

Normally primary alcohols undergo SN2 easily, but since all are primary in the given options, lets consider other factors.

In option 3, we have an allylic halide and we know allylic carbocation is very stable, so option 3 is more likely to undergo an SN1 rather than SN2.

83) 1

This is an SN1 process, which means a carbocation intermediate is formed first.

In terms of stability,

Tertiary carbocation > secondary carbocation > primary carbocation

As tertiary carbocation is more stable, tertiary alcohol is the most reactive.

So option 1 is right.

84) 4

Grignards' reagent is RMgX.

R- alkyl group (like -CH3, -C2H5, etc)

Mg- magnesium

X- halide

85) 2

Ethylidene chloride is CHCl2-CH3.

When it reacts with aqueous KOH, both Cl atoms are replaced by OH.

Finally we get Acetaldehyde a the product.

86) 3

In the reaction of CCl4 and AgNO3, AgCl can be formed only when Chloride ion is formed.

But here CCl3^- ion is more stable and thus CCl4 gives CCl3^- and Cl^+ thereby not forming AgCl.

87) 1

Explanation is in the attachment below.

88) 2

Saytzeff rule:

Hydrogen is preferentially lost from the carbon having less number of hydrogens.

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