Answer all the 3 questions.
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Answered by
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hey mate
here is your answer
129- v of the coil=200 v
I in the coil=10A
therefore, r of the coil=v/I
=200/10
=20 ohm
the equivalent resistance of 20 Ohm, 60 ohm and 35 ohm
=1÷(1/20+1/60)+35
=1÷1/15+35
=15+35
=50
the current in the circuit=200/50
=4A
hence the heat energy=i²rt
=(4)²*50*5*60
=4²*50*300
=16*50*300
=540000
=5.4*10^5 j
130-the equivalent resistance of 40 Ohm 60 ohm and 50 Ohm=150 ohm
the potential difference=200 v
therefore the current=200/150
=4/3
131-when the object has covered half way
then half of its kinetic energy gets converted into potential energy
hence kinetic energy =1/2 of potential energy
800=1/2*mgh
1600=500/1000*10*h
1600=5*h
h=320 m (answer)
here is your answer
129- v of the coil=200 v
I in the coil=10A
therefore, r of the coil=v/I
=200/10
=20 ohm
the equivalent resistance of 20 Ohm, 60 ohm and 35 ohm
=1÷(1/20+1/60)+35
=1÷1/15+35
=15+35
=50
the current in the circuit=200/50
=4A
hence the heat energy=i²rt
=(4)²*50*5*60
=4²*50*300
=16*50*300
=540000
=5.4*10^5 j
130-the equivalent resistance of 40 Ohm 60 ohm and 50 Ohm=150 ohm
the potential difference=200 v
therefore the current=200/150
=4/3
131-when the object has covered half way
then half of its kinetic energy gets converted into potential energy
hence kinetic energy =1/2 of potential energy
800=1/2*mgh
1600=500/1000*10*h
1600=5*h
h=320 m (answer)
Answered by
0
1) option c
2)option b
3)option a
have a nice day:)
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