Question

Answer ALL the following questions:
Force exerted by 5nC on 3nC is 2N. What is the force on 5nCdue to 30nC​

Answer 1

Answer:

The force between 5 nC , 30 nC is 20 N  

Explanation:

Given as :

Force exerted between two charged 5 nC , 3 nC = 2 N

Or, $q_1$  =  5 nC

     $q_2$  =  3 nC

A/Q

electrostatic force = F = k × $\dfrac{q_1 q_2}{d^{2} }$     , where k = $\dfrac{1}{4\Pi \varepsilon _0}$

Or, 2 N =  k × $\dfrac{5\times 3}{d^{2}}$

Or, $\dfrac{k}{d^{2} }$  = $\dfrac{2}{15}$           ........1

Again

For charges

$q_3$ = 5 nC

$q_4$ = 3 nC

Force = F' =  k × $\dfrac{q_1 q_2}{d^{2} }$

Or, F' = $\dfrac{2}{15}$  × $q_1$ × $q_2$

Or, F' = $\dfrac{2}{15}$  × 5 × 30

∴  F' = 20 N

so, Force = F' = 20 N

Hence, The force between 5 nC , 30 nC is 20 N  . Answer