Question

Answer all the questions :

(1. 29). Calculate the molarity of a solution of ethanol in water in which the mole fraction of ethanol is 0.040 ?

(1. 30). What will be the mass of 12C atom in g ?

First and best answer will be marked as brainliest.​

Answer 1

Answer :

Molarity = No of moles/Volume

Moles of Ethanol = 0.04 Mol

Moles of Water = 1-0.04 = 0.96

Mass of water = 0.96*18 = 17.3

Mass of ethanol = 0.04*46 = 1.84g

Therefore Total mass of the solution = 17.3 + 1.84 = 19.1g

Density = 1g/mL (Assumed)

Density = mass/volume so volume = mass/density

= 19.1/1 = 19.1mL = 0.0191L

hence Molarity = 0.04/0.0191

= 2.1M

$\rule{100}{2}$

The mass of a single atom of Carbon 12 is simply the mass of a mole of the stuff (12 grams) divided by Avogadro's number (6.022 x 1023). That works out to 1.9927 x 10-23 grams. ... It is "the product of 12 amu*1.66*10^-24 grams".

Answer 2

Answer:

Molarity = No of moles/Volume

Moles of Ethanol = 0.04 Mol

Moles of Water = 1-0.04 = 0.96

Mass of water = 0.96*18 = 17.3

Mass of ethanol = 0.04*46 = 1.84g

Therefore Total mass of the solution = 17.3 + 1.84 = 19.1g

Density = 1g/mL (Assumed)

Density = mass/volume so volume = mass/density

= 19.1/1 = 19.1mL = 0.0191L

hence Molarity = 0.04/0.0191

= 2.1M

$$\rule{100}{2}$$

The mass of a single atom of Carbon 12 is simply the mass of a mole of the stuff (12 grams) divided by Avogadro's number (6.022 x 1023). That works out to 1.9927 x 10-23 grams.It is "the product of 12 amu*1.66*10^-24 grams".