Question

Answer all the questions:
1. Find the area of an isosceles triangle whose base is 12 cm and height is 32 cm

Answer 1

Answer:

Area of isosceles triangle = 1/2 Base × height 1/2×12×32

6×32

192

Answer 2

Given that , The Base and Height of an Isosceles Triangle are 12 cm & 32 cm , respectively.

Need To Find : Area of an Isosceles triangle ?

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⠀▪︎ We've the Base & Height of Triangle . Formula to find Area of Triangle is Given by —

$\qquad \star\:\underline {\boxed {\pmb {\frak{ \:\:Area _{\:( Triangle )\:}\:=\:\dfrac{1}{2}\:\times\:Base \:\times \:Height \:\:\:sq.units\:}}}}$

⠀⠀⠀Here , Base of Triangle is 12 cm & Height of Triangle is 32 cm .

$\\\dag \:\underline {\frak{Putting \:known \:Values \:in \:Formula \:\::\:}}$

$\qquad \dashrightarrow \sf \:\:Area _{\:( Triangle )\:}\:=\:\dfrac{1}{2}\:\times\:Base \:\times \:Height \:\\\\\\ \qquad \dashrightarrow \sf \:\:Area _{\:( Triangle )\:}\:=\:\dfrac{1}{2}\:\times\:12 \:\times \:32 \:\\\\\\ \qquad \dashrightarrow \sf \:\:Area _{\:( Triangle )\:}\:=\:\dfrac{1}{\cancel {2}}\:\times\:\cancel {12} \:\times \:32 \:\\\\\\ \qquad \dashrightarrow \sf \:\:Area _{\:( Triangle )\:}\:=\:\:6 \:\times \:32 \:\\\\\\ \qquad \dashrightarrow \underline {\boxed {\pmb{\frak{\purple {\:\:Area _{\:( Triangle )\:}\:=\:\:192\:cm^2 \:}}}}}\:\:\bigstar \:$

$\\\therefore \:\underline {\sf Hence, \:The \:Area \:of \:Triangle \:is \:\:\pmb{\bf\: \: 192 \:cm^2 \:}\:.}$