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Answer:
2)40 m
3)64 cm
4)3 km
5)Increase in perimeter of rectangle
6)13 cm
7)65 m 40 cm
8)99000 rs
9)Smita walk 60m more than Ranjan
10)154875 rs
11)Length = 20 m and Breadth 5 m
Step-by-step explanation:
2) Shamim have to walk around square field that means we have to found perimeter of square
Given,
a=10m
perimeter of square = 4a
=4(10)
=40m
3)We have to find perimeter of rectangle
Given,
a = 20 cm , b = 12 cm
perimeter of rectangle = 2(a+b)
=2(20+12)
=2(32)
=64 cm
therefore , 64 cm of coloured required to stick on rectangular scenery.
4)Given,
a = 1 km = 1000 m , b = 500 m
perimeter of rectangle = 2(a+b)
= 2(1000+500)
= 2(1500)
= 3000 m
= 3 km
5)let length of rectangle be a and breadth of rectangle be b
perimeter of rectangle = 2(a+b)
According to condition , length double and breadth remain same
perimeter of rectangle = 2(2a+b)
therefore , there will be increase in perimeter of rectangle.
6)Given,
a = 10cm , b = 12 cm , c = ? cm
perimeter of triangle = 35 cm
a+b+c = 35 cm
10 + 12 + c = 35
c = 13 cm
therefore , third side of triangle is 13 cm.
7)Given,
a = 20 m 50 cm = (20*100+50)cm = 2050 cm [1m = 100 cm]
b = 12 m 20 cm = (12*100+20)cm = 1220 cm
perimeter of rectangular lawn = 2(2050+1220)
= 6540 cm
= 65 m 40 cm
therefore , perimeter of lawn is 65 m 40 cm
8)Given,
a = 0.6 km = 600 m , b = 0.5 km = 500 m
perimeter of rectangle = 2(a+b) = 2(600+500) = 2(1100) = 2200 m
For 1 row of wire required around rectangular lawn is 2200 m.
so, for 5 row wire required = 2200*5
= 11000 m
cost for per m of wire = 9 rs
total cost = 11000*9
= 99000 rs
Total cost required to fence rectangular lawn is 99000rs .
9)For Ranjan,
a = 60 m , b = 40 m
perimeter of rectangle = 2(a+b) = 2(60+40) = 200 m
distance covered in 3 rounds = 200*3 = 600m
For Simta,
a = 55m
perimeter of square = 4a = 4*55 = 220 m
distance covered in 3 rounds = 660 m
therefore , Smita walk 60m more than Ranjan
10)Given,
a = 250 m , b = 200 m
perimeter of rectangle = 2(a+b) = 2(250+200) = 900 m
perimeter of fencing = 900 - 10 - 5 = 885 m (exclude gate and exit gate)
cost required per meter = 175 rs
total cost = 175 * 885
= 154875 rs
therefore , total cost for fencing is 154875 rs
11)Given,
a = 15 m , b = 10 m
perimeter of rectangle = 2(a+b) = 2 =(15+10) = 50 m
given that perimeter of rectangle is same for another rectangle
sides of another rectangle is in the ratio 4:1
let, a = 4x and b = x
perimeter of rectangle = 2(a+b)
50 = 2(4x+x)
50 = 2(5x)
50 = 10x
x = 5
so , a = 4x = 4*5 = 20 m
b = x = 5 m
length and breadth of new reactangle is 20 m and 5 m respectively