Question

Answer all these questions please

Answer 1

Answer:

1st Question:

Given:

Mass of 2 kg travelling in a circular path at a speed of 10 m/s . Radius of path is

1 metre.

To find:

Angular speed in rad/sec.

Calculation:

Let angular velocity be denoted by ω,

linear velocity is V and radius is r

ω = V/r

=> ω = 10/1

=> ω = 10 rad/sec. ( option B)

2nd question:

Given:

Ratio of radii = 1:2

But time taken is same.

To find:

Ratio of linear speed

Calculation:

Speed = Distance/time.

Let the radius be x and 2x

so for 1st object:

speed = 2πx/T

so for 2nd object:

speed = 2π(2x)/T

So ratio =[ 2πx/T ] : [2π(2x)/T]

=> ratio = 1:2 ( option A)

Answer 2

◦•●◉✿ solution ✿◉●•◦

1.

Angular Velocity is the rate of change of angle when a body travels in a circular path.

ω is use to represent angular velocity.

In physics angular velocity can be written in form of TANGENTIAL velocity or simple linear velocity (v) as

ω = V/r

where r is the radii of the circular path

ACC to question v = 10m and r = 1m

ω = 10radian/sec.

2.

As we discussed above about the angular velocity....

In this question ω of both the bodies is equal as it cover equal Angle in equal interval of time.

Let ω(1) be the angular velocity of first body

Let ω(2) be the angular velocity of the second body.

ω(1) = ω(2)

v(1)/R(1) = v(2)/R(2)

v(1)/v(2) = R(1)/R(2)........1

R(1)/R(2) = 1:2....put in 1

v(1)/v(2) = 1/2

v(1):v(2) = 1:2

#answerwithquality

#BAL