Answer and explain if you want to be brainliest :)
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Answer:
Let f(u)=4u
2 +8u
To calculate the zeros of the given equation, put f(u)=0.
4u 2 +8u=0
4u(u+2)=0
u=0,u=−2
The zeros of the given equation is 0 and −2.
Sum of the zeros is 0+(−2)=−2.
Product of the zeros is 0×−2=0.
According to the given equation,
The sum of the zeros is,
a−b = 4−(8)=−2
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